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 is a point on the side  of a triangle  such that . Show that .

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In △ADC and △BAC


∠ADC=∠BAC (Given)

∠C is Common

answer
 by AA Criterion of Similarity, △ADC  △BAC


⇒BAAD=ACDC=BCAC

⇒ACDC=BCAC


 CA2=CB.CD

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